C LANGUAGE SYNTAX PROGRAM part I

PART I ==> simple calculator

# include <stdio.h>
# include <conio.h>
main ()
{
float x, y, add, less, times, for;
printf ("\ t PROGRAM CALCULATOR \ n");
printf ("Input number # 1:"); scanf ("% f", & x);
printf ("Input number # 2:");
scanf ("% f", & y);

added  = x + y;
less   = x-y;
time   = x * y;
for    = x / y;

printf ("\ n Results% .1 f +% .1 f =% .1 f", x, y, add);
printf ("\ n Results% .1 f -% .1 f =% .1 f", x, y, or less);
printf ("\ n Results% .1 f x% .1 f =% .1 f", x, y, time);
printf ("\ n Results% .1 f:% .1 f  =% .2 f", x, y, for);

printf ("\ n Results% .1 f% c =% .1 f \ n", x, 1, sqrt (x));
getch ();
}

Save with the extension. C


Display program 

CALCULATOR PROGRAM

Input number into-1  : 4
Input numbers into-2 : 5
Results 4.0 + 5.0  = 9.0
Results 4.0 - 5.0  = -1.0
Results 4.0 X 5.0  = 20.0
Results 4.0 : 5.0  = 0.80
Results 4.0 ☺      = 2.0 

Description of program:

The program above will perform simple arithmetic functions  on figures that have been fed. As already described in the previous tutorial, that the function of 'printf ()' which is to display the output to the screen and the function 'scanf ()' for reading the input data. Operators are in use in the above program is the addition operator (+), reduction (-), multiplication (x), division (:) and the square root ( smile ) hehehee,, sorry I have not met the square root ascii code. OK ..., it seems easy enough until here ... to deepen knowledge in C programming language, you can see in my next tutorial,, see you ....!  

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